(3x+18)(x^2-x-30)/(x^2-36)(4x-12)

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Solution for (3x+18)(x^2-x-30)/(x^2-36)(4x-12) equation: 


D( x )

x^2-36 = 0

x^2-36 = 0

x^2-36 = 0

1*x^2 = 36 // : 1

x^2 = 36

x^2 = 36 // ^ 1/2

abs(x) = 6

x = 6 or x = -6

x in (-oo:-6) U (-6:6) U (6:+oo)

(((3*x+18)*(x^2-x-30))/(x^2-36))*(4*x-12) = 0

((3*x+18)*(x^2-x-30)*(4*x-12))/(x^2-36) = 0

x^2-x-30 = 0

x^2-x-30 = 0

DELTA = (-1)^2-(-30*1*4)

DELTA = 121

DELTA > 0

x = (121^(1/2)+1)/(1*2) or x = (1-121^(1/2))/(1*2)

x = 6 or x = -5

(x+5)*(x-6) = 0

((3*x+18)*(x+5)*(x-6)*(4*x-12))/(x^2-36) = 0

( 3*x+18 )

3*x+18 = 0 // - 18

3*x = -18 // : 3

x = -18/3

x = -6

( 4*x-12 )

4*x-12 = 0 // + 12

4*x = 12 // : 4

x = 12/4

x = 3

( x+5 )

x+5 = 0 // - 5

x = -5

( x-6 )

x-6 = 0 // + 6

x = 6

x in { -6} 

x in { 6} 

x in { 3, -5 }

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